What is (x^2-9)/(x^2+7x+12) ?

The solution to (x^2-9)/(x^2+7x+12) is (x-3)/(x+4)

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simplify (x^2-9)/(x^2+7x+12)

simplify

\frac{x ^{2} - 9}{x ^{2} + 7 x + 12}

\frac{x - 3}{x + 4}

Solution steps

\frac{x ^{2} - 9}{x ^{2} + 7 x + 12}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} + 7 x + 12}

Factor

x^{2} + 7 x + 12 : (x + 3) (x + 4)

= \frac{( x + 3 ) ( x - 3 )}{( x + 3 ) ( x + 4 )}

Cancel the common factor:

x + 3

= \frac{x - 3}{x + 4}

\frac{5}{2} \div \frac{9}{4}

\frac{30 a ^{6} b ^{10} + 12 a ^{4} b ^{6} - 9 a ^{10} b ^{4}}{3 ab}

\frac{8 - x}{8 + x}

3 x^{2} + 15 x - 18

\frac{16 m ^{2} - 4 m - 6}{4 m + 2}

What is (x^2-9)/(x^2+7x+12) ?
The solution to (x^2-9)/(x^2+7x+12) is (x-3)/(x+4)