What is (-3x^2+4x+10)-(2x^2-2x) ?

The solution to (-3x^2+4x+10)-(2x^2-2x) is -5x^2+6x+10

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simplify (-3x^2+4x+10)-(2x^2-2x)

simplify

(- 3 x^{2} + 4 x + 10) - (2 x^{2} - 2 x)

- 5 x^{2} + 6 x + 10

Solution steps

(- 3 x^{2} + 4 x + 10) - (2 x^{2} - 2 x)

Apply rule:

(a) = a

(- 3 x^{2} + 4 x + 10) = - 3 x^{2} + 4 x + 10

= - 3 x^{2} + 4 x + 10 - (2 x^{2} - 2 x)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{2} - 2 x) = - 2 x^{2} + 2 x

= - 3 x^{2} + 4 x + 10 - 2 x^{2} + 2 x

Group like terms

= - 3 x^{2} - 2 x^{2} + 4 x + 2 x + 10

Add similar elements:

- 3 x^{2} - 2 x^{2} = - 5 x^{2}

= - 5 x^{2} + 4 x + 2 x + 10

Add similar elements:

4 x + 2 x = 6 x

= - 5 x^{2} + 6 x + 10

\frac{45}{18}

ln (0.96)

(9 + 4 x)^{2}

tan (x) cos (x) + sin^{2} (x) csc (x)

(- x^{2} + 2 x - 1) (2 x^{2} + 4 x - 1)

What is (-3x^2+4x+10)-(2x^2-2x) ?
The solution to (-3x^2+4x+10)-(2x^2-2x) is -5x^2+6x+10