What are the solutions to the equation 9x(2x+1)=5 ?

The solutions to the equation 9x(2x+1)=5 are x= 1/3 ,x=-5/6

Find the zeros of 9x(2x+1)=5

The zeros of 9x(2x+1)=5 are x= 1/3 ,x=-5/6

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9 x (2 x + 1) = 5

x = \frac{1}{3}, x = - \frac{5}{6}

Solution steps

9 x (2 x + 1) = 5

Expand

9 x (2 x + 1) : 18 x^{2} + 9 x

18 x^{2} + 9 x = 5

Move

5

to the left side

18 x^{2} + 9 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 18 ( - 5 )}{2 \cdot 18}

9^{2} - 4 \cdot 18 (- 5) = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 \cdot 18}, x_{2} = \frac{- 9 - 21}{2 \cdot 18}

x = \frac{- 9 + 21}{2 \cdot 18} : \frac{1}{3}

x = \frac{- 9 - 21}{2 \cdot 18} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{5}{6}

(\frac{1 + i}{1 - i})^{2}

\frac{g}{2} \geq 2

2 n - 2

x^{4} - 34 x^{2} + 225

4 x^{2} = 320

What are the solutions to the equation 9x(2x+1)=5 ?
The solutions to the equation 9x(2x+1)=5 are x= 1/3 ,x=-5/6
Find the zeros of 9x(2x+1)=5
The zeros of 9x(2x+1)=5 are x= 1/3 ,x=-5/6