What is (30x^3-18x^2)/(6x^3+5x^2)*(42x+35)/(60x-36) ?

The solution to (30x^3-18x^2)/(6x^3+5x^2)*(42x+35)/(60x-36) is 7/2

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simplify (30x^3-18x^2)/(6x^3+5x^2)*(42x+35)/(60x-36)

simplify

\frac{30 x ^{3} - 18 x ^{2}}{6 x ^{3} + 5 x ^{2}} \cdot \frac{42 x + 35}{60 x - 36}

\frac{7}{2}

Decimal Notation

3.5

Solution steps

\frac{30 x ^{3} - 18 x ^{2}}{6 x ^{3} + 5 x ^{2}} \cdot \frac{42 x + 35}{60 x - 36}

Cancel

\frac{30 x ^{3} - 18 x ^{2}}{6 x ^{3} + 5 x ^{2}} : \frac{6 ( 5 x - 3 )}{6 x + 5}

= \frac{6 ( 5 x - 3 )}{6 x + 5} \cdot \frac{42 x + 35}{60 x - 36}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{6 ( 5 x - 3 ) ( 42 x + 35 )}{( 6 x + 5 ) ( 60 x - 36 )}

Factor

42 x + 35 : 7 (6 x + 5)

= \frac{6 ( 5 x - 3 ) \cdot 7 ( 6 x + 5 )}{( 6 x + 5 ) ( 60 x - 36 )}

Cancel the common factor:

6 x + 5

= \frac{6 ( 5 x - 3 ) \cdot 7}{60 x - 36}

Factor

60 x - 36 : 12 (5 x - 3)

= \frac{6 ( 5 x - 3 ) \cdot 7}{12 ( 5 x - 3 )}

Cancel the common factor:

5 x - 3

= \frac{6 \cdot 7}{12}

Factor the number:

12 = 6 \cdot 2

= \frac{6 \cdot 7}{6 \cdot 2}

Cancel the common factor:

6

= \frac{7}{2}

(2 x + 3) (3 - x) - (2 x - 5) (3 - x)

(53 - 48) \cdot 12

\frac{( 4 a ) ^{2}}{4 a ^{9}}

(x + \frac{1}{3})^{3}

(a^{- 1})^{3}

What is (30x^3-18x^2)/(6x^3+5x^2)*(42x+35)/(60x-36) ?
The solution to (30x^3-18x^2)/(6x^3+5x^2)*(42x+35)/(60x-36) is 7/2