What is (1-x)/(x^2-3x+2) ?

The solution to (1-x)/(x^2-3x+2) is -1/(x-2)

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simplify (1-x)/(x^2-3x+2)

simplify

\frac{1 - x}{x ^{2} - 3 x + 2}

- \frac{1}{x - 2}

Solution steps

\frac{1 - x}{x ^{2} - 3 x + 2}

Factor

x^{2} - 3 x + 2 : (x - 1) (x - 2)

= \frac{1 - x}{( x - 1 ) ( x - 2 )}

1 - x = - (x - 1)

= \frac{- ( x - 1 )}{( x - 1 ) ( x - 2 )}

Cancel the common factor:

x - 1

= \frac{- 1}{x - 2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{x - 2}

(3 y^{\frac{2}{3}})^{3} (2 y^{2})^{2}

40 x^{2} - 48

1 \times 4

n \cdot n

(- 3 x y^{5})^{4}