What is (3x)/(2x+2)*(x^2-1)/(x^2+6x-7) ?

The solution to (3x)/(2x+2)*(x^2-1)/(x^2+6x-7) is (3x)/(2(x+7))

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simplify (3x)/(2x+2)*(x^2-1)/(x^2+6x-7)

simplify

\frac{3 x}{2 x + 2} \cdot \frac{x ^{2} - 1}{x ^{2} + 6 x - 7}

\frac{3 x}{2 ( x + 7 )}

Solution steps

\frac{3 x}{2 x + 2} \cdot \frac{x ^{2} - 1}{x ^{2} + 6 x - 7}

Cancel

\frac{x ^{2} - 1}{x ^{2} + 6 x - 7} : \frac{x + 1}{x + 7}

= \frac{3 x}{2 x + 2} \cdot \frac{x + 1}{x + 7}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 x ( x + 1 )}{( 2 x + 2 ) ( x + 7 )}

Factor

2 x + 2 : 2 (x + 1)

= \frac{3 x ( x + 1 )}{2 ( x + 1 ) ( x + 7 )}

Cancel the common factor:

x + 1

= \frac{3 x}{2 ( x + 7 )}

⌊ 3 ⌋

\frac{d}{d x} (ln (x^{2} + y^{2}))

\frac{1}{k} - \frac{1}{k + 1}

4 (2 y + 3)

What is (3x)/(2x+2)*(x^2-1)/(x^2+6x-7) ?
The solution to (3x)/(2x+2)*(x^2-1)/(x^2+6x-7) is (3x)/(2(x+7))