What is expand (2x+1)/((x-3)^2) ?

The solution to expand (2x+1)/((x-3)^2) is (2x+1)/(x^2-6x+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x+1)/((x-3)^2)

expand

\frac{2 x + 1}{( x - 3 ) ^{2}}

\frac{2 x + 1}{x ^{2} - 6 x + 9}

Solution steps

\frac{2 x + 1}{( x - 3 ) ^{2}}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{2 x + 1}{x ^{2} - 6 x + 9}

(x + 2)^{2}

\frac{3 x - 1}{( x + 3 ) ( x - 2 )}

(1 + cos (x)) (csc (x) - cot (x))

(z^{3} + 3 z + 1)^{6}

(1 + e^{2 t})^{2}

What is expand (2x+1)/((x-3)^2) ?
The solution to expand (2x+1)/((x-3)^2) is (2x+1)/(x^2-6x+9)