What is expand (3x+2y=2,)(x-y=9) ?

The solution to expand (3x+2y=2,)(x-y=9) is 3x^2-3xy=9

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expand (3x+2y=2,)(x-y=9)

expand

(3 x + 2 y = 2,) (x - y = 9)

3 x^{2} - 3 x y = 9

Solution steps

(3 x + 2 y = 2,) (x - y = 9)

= (3 x + 2 \cdot 2 =, y) (x - 9 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 3 x, b = 2 y = 2,, c = x, d = - y = 9

3 xx + 3 x (- y = 9) + 2 y = 2, x + 2 y = 2, (- y = 9)

Apply minus-plus rules

+ (- a) = - a

3 xx - 3 x y = 9 + 2 y = 2, x - 2 y = 2, y = 9

Expand

3 xx - 3 x y : 3 x^{2} - 3 x y

3 x^{2} - 3 x y = 9

(x + 3)^{2}

(e^{t} + e^{2 t})^{2}

\frac{1}{( x + 1 ) ^{2}}

(x - 2)^{2}

\frac{3 x}{( x + 5 ) ( x + 3 )}

What is expand (3x+2y=2,)(x-y=9) ?
The solution to expand (3x+2y=2,)(x-y=9) is 3x^2-3xy=9