What is factor 5x^2(2x^2+1)^4(6x)+(2x^2+1)^5(2x) ?

The solution to factor 5x^2(2x^2+1)^4(6x)+(2x^2+1)^5(2x) is 2x(2x^2+1)^4(17x^2+1)

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factor 5x^2(2x^2+1)^4(6x)+(2x^2+1)^5(2x)

factor

5 x^{2} (2 x^{2} + 1)^{4} (6 x) + (2 x^{2} + 1)^{5} (2 x)

2 x (2 x^{2} + 1)^{4} (17 x^{2} + 1)

Solution steps

5 x^{2} (2 x^{2} + 1)^{4} (6 x) + (2 x^{2} + 1)^{5} (2 x)

Factor out common term

(2 x^{2} + 1)^{4} : (2 x^{2} + 1)^{4} (5 x^{2} \cdot 6 x + (2 x^{2} + 1) \cdot 2 x)

= (2 x^{2} + 1)^{4} (5 x^{2} \cdot 6 x + (2 x^{2} + 1) \cdot 2 x)

Factor

5 x^{2} \cdot 6 x + (2 x^{2} + 1) \cdot 2 x : 2 x (17 x^{2} + 1)

= (2 x^{2} + 1)^{4} \cdot 2 x (17 x^{2} + 1)

= 2 x (2 x^{2} + 1)^{4} (17 x^{2} + 1)

- 3 x - 5 = 5 x - 61

36 w^{2} - 121

4 x^{2} - 8 x - 60

1^{2} + b^{2} = 5^{2}

\frac{3 - 5 y}{4} = \frac{2 - 4 y}{3}

What is factor 5x^2(2x^2+1)^4(6x)+(2x^2+1)^5(2x) ?
The solution to factor 5x^2(2x^2+1)^4(6x)+(2x^2+1)^5(2x) is 2x(2x^2+1)^4(17x^2+1)