What is expand (1+sin(θ))^2 ?

The solution to expand (1+sin(θ))^2 is 1+2sin(θ)+sin^2(θ)

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expand (1+sin(θ))^2

expand

(1 + sin (θ))^{2}

1 + 2 sin (θ) + sin^{2} (θ)

Solution steps

(1 + sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(1 + sin (θ))^{2} = 1^{2} + 2 \cdot 1 \cdot sin (θ) + sin^{2} (θ)

= 1^{2} + 2 \cdot 1 \cdot sin (θ) + sin^{2} (θ)

Simplify

1^{2} + 2 \cdot 1 \cdot sin (θ) + sin^{2} (θ) : 1 + 2 sin (θ) + sin^{2} (θ)

= 1 + 2 sin (θ) + sin^{2} (θ)

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

(3 + i)^{4}

\frac{6}{( s ^{2} - 4 s + 20 ) ^{2}}

(3 + 3 i)^{5}

(x + i y)^{5}

What is expand (1+sin(θ))^2 ?
The solution to expand (1+sin(θ))^2 is 1+2sin(θ)+sin^2(θ)