What is expand ((1-x)^3)/3 ?

The solution to expand ((1-x)^3)/3 is -(x^3)/3+x^2-x+1/3

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expand ((1-x)^3)/3

expand

\frac{( 1 - x ) ^{3}}{3}

- \frac{x ^{3}}{3} + x^{2} - x + \frac{1}{3}

Solution steps

\frac{( 1 - x ) ^{3}}{3}

(1 - x)^{3} = 1 - 3 x + 3 x^{2} - x^{3}

= \frac{1 - 3 x + 3 x ^{2} - x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 3 x + 3 x ^{2} - x ^{3}}{3} = \frac{1}{3} - \frac{3 x}{3} + \frac{3 x ^{2}}{3} - \frac{x ^{3}}{3}

= \frac{1}{3} - \frac{3 x}{3} + \frac{3 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{3}{3} = 1

= \frac{1}{3} - x + x^{2} - \frac{x ^{3}}{3}

Rewrite in standard form

= - \frac{x ^{3}}{3} + x^{2} - x + \frac{1}{3}

\frac{1}{( x - 3 ) ^{2}}

(2 sin (x) + 2 cos (x))^{2}

(x + 32)^{2}

(ln (x) + 1)^{2}

(sec (θ) + csc (θ)) (cos (θ) - sin (θ))

What is expand ((1-x)^3)/3 ?
The solution to expand ((1-x)^3)/3 is -(x^3)/3+x^2-x+1/3