What is expand (e^x+e^{-x})(e^x-e^{-x}) ?

The solution to expand (e^x+e^{-x})(e^x-e^{-x}) is e^{2x}-e^{-2x}

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expand (e^x+e^{-x})(e^x-e^{-x})

expand

(e^{x} + e^{- x}) (e^{x} - e^{- x})

e^{2 x} - e^{- 2 x}

Solution steps

(e^{x} + e^{- x}) (e^{x} - e^{- x})

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = e^{x}, b = e^{- x}

= (e^{x})^{2} - (e^{- x})^{2}

Simplify

(e^{x})^{2} - (e^{- x})^{2} : e^{2 x} - e^{- 2 x}

= e^{2 x} - e^{- 2 x}

[g (e^{x} - 2 x^{3})]^{\frac{1}{2}}

(1 + 2 i)^{6}

\frac{4 x}{( x ^{2} + 1 ) ^{2}}

x^{\frac{1}{5}} (x + 6)

(x - 5)^{2}

What is expand (e^x+e^{-x})(e^x-e^{-x}) ?
The solution to expand (e^x+e^{-x})(e^x-e^{-x}) is e^{2x}-e^{-2x}