What is expand-(8x)/((x^2-4)^2) ?

The solution to expand-(8x)/((x^2-4)^2) is -(8x)/(x^4-8x^2+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(8x)/((x^2-4)^2)

expand

- \frac{8 x}{( x ^{2} - 4 ) ^{2}}

- \frac{8 x}{x ^{4} - 8 x ^{2} + 16}

Solution steps

- \frac{8 x}{( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= - \frac{8 x}{x ^{4} - 8 x ^{2} + 16}

(3 - i)^{4}

(1 - 2 i)^{5}

(\frac{4}{16} x + \frac{5}{16} y + \frac{3}{16} z + \frac{4}{16} u)^{4}

\frac{- x ^{2} + y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

(2 + i)^{5}

What is expand-(8x)/((x^2-4)^2) ?
The solution to expand-(8x)/((x^2-4)^2) is -(8x)/(x^4-8x^2+16)