What are the solutions to the equation 4^2+1^2=c^2 ?

The solutions to the equation 4^2+1^2=c^2 are c=sqrt(17),c=-sqrt(17)

Find the zeros of 4^2+1^2=c^2

The zeros of 4^2+1^2=c^2 are c=sqrt(17),c=-sqrt(17)

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4^{2} + 1^{2} = c^{2}

c = 17, c = - 17

Decimal Notation

c = 4.12310 \dots, c = - 4.12310 \dots

Solution steps

4^{2} + 1^{2} = c^{2}

Switch sides

c^{2} = 4^{2} + 1^{2}

Simplify

4^{2} + 1^{2} : 17

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 17, c = - 17

4 x^{2} + 9 x < 9

5 x - 9 \geq 11

\frac{7}{3}

2 + 2 x - 3 = 6 - x - 1

- \frac{4}{7} - \frac{8}{9} + \frac{4}{7} + \frac{9}{8}

What are the solutions to the equation 4^2+1^2=c^2 ?
The solutions to the equation 4^2+1^2=c^2 are c=sqrt(17),c=-sqrt(17)
Find the zeros of 4^2+1^2=c^2
The zeros of 4^2+1^2=c^2 are c=sqrt(17),c=-sqrt(17)