What is expand ((x^2-9)(x-3)(x-1))/((x+1)(x+2)) ?

The solution to expand ((x^2-9)(x-3)(x-1))/((x+1)(x+2)) is (x^4-4x^3-6x^2+36x-27)/(x^2+3x+2)

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expand ((x^2-9)(x-3)(x-1))/((x+1)(x+2))

expand

\frac{( x ^{2} - 9 ) ( x - 3 ) ( x - 1 )}{( x + 1 ) ( x + 2 )}

\frac{x ^{4} - 4 x ^{3} - 6 x ^{2} + 36 x - 27}{x ^{2} + 3 x + 2}

Solution steps

\frac{( x ^{2} - 9 ) ( x - 3 ) ( x - 1 )}{( x + 1 ) ( x + 2 )}

Expand

(x + 1) (x + 2) : x^{2} + 3 x + 2

= \frac{( x ^{2} - 9 ) ( x - 3 ) ( x - 1 )}{x ^{2} + 3 x + 2}

Expand

(x^{2} - 9) (x - 3) (x - 1) : x^{4} - 4 x^{3} - 6 x^{2} + 36 x - 27

= \frac{x ^{4} - 4 x ^{3} - 6 x ^{2} + 36 x - 27}{x ^{2} + 3 x + 2}

\frac{1}{( 1 - x ) ^{3}}

\frac{x + 1}{x ( x + 4 )}

(2 + x)^{2}

(1 + cos (t))^{2}

What is expand ((x^2-9)(x-3)(x-1))/((x+1)(x+2)) ?
The solution to expand ((x^2-9)(x-3)(x-1))/((x+1)(x+2)) is (x^4-4x^3-6x^2+36x-27)/(x^2+3x+2)