What is ((7x)/3-(sqrt(y))/5)((7x)/3+(sqrt(y))/5) ?

The solution to ((7x)/3-(sqrt(y))/5)((7x)/3+(sqrt(y))/5) is (1225x^2-9y)/(225)

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simplify ((7x)/3-(sqrt(y))/5)((7x)/3+(sqrt(y))/5)

simplify

(\frac{7 x}{3} - \frac{y}{5}) (\frac{7 x}{3} + \frac{y}{5})

\frac{1225 x ^{2} - 9 y}{225}

Solution steps

(\frac{7 x}{3} - \frac{y}{5}) (\frac{7 x}{3} + \frac{y}{5})

Simplify

\frac{7 x}{3} - \frac{y}{5} : \frac{35 x - 3 y}{15}

= \frac{35 x - 3 y}{15} (\frac{7 x}{3} + \frac{y}{5})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 35 x - 3 y ) ( \frac{7 x}{3} + \frac{y}{5} )}{15}

Simplify

(35 x - 3 y) (\frac{7 x}{3} + \frac{y}{5}) : \frac{1225 x ^{2} - 9 y}{15}

= \frac{\frac{1225 x ^{2} - 9 y}{15}}{15}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1225 x ^{2} - 9 y}{15 \cdot 15}

Multiply the numbers:

15 \cdot 15 = 225

= \frac{1225 x ^{2} - 9 y}{225}

(x + 6) (x - 6)

\frac{12 x ^{3} - 37 x ^{2} + 48 x - 36}{( x - 2 ) ^{2} ( x ^{2} + 4 )}

(x - 2 + 6) (x - 2 - 6)

cos (a) (sec (a) - cos (a))

(1 - cos (a)) (1 + cos (a))

What is ((7x)/3-(sqrt(y))/5)((7x)/3+(sqrt(y))/5) ?
The solution to ((7x)/3-(sqrt(y))/5)((7x)/3+(sqrt(y))/5) is (1225x^2-9y)/(225)