What is expand (e^x-e^{-x})(e^x+e^{-x}) ?

The solution to expand (e^x-e^{-x})(e^x+e^{-x}) is e^{2x}-e^{-2x}

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expand (e^x-e^{-x})(e^x+e^{-x})

expand

(e^{x} - e^{- x}) (e^{x} + e^{- x})

e^{2 x} - e^{- 2 x}

Solution steps

(e^{x} - e^{- x}) (e^{x} + e^{- x})

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{x}, b = e^{- x}

= (e^{x})^{2} - (e^{- x})^{2}

Simplify

(e^{x})^{2} - (e^{- x})^{2} : e^{2 x} - e^{- 2 x}

= e^{2 x} - e^{- 2 x}

\frac{1}{( 2 - x ) ^{2}}

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(\frac{2}{3} x - \frac{3}{5} y) (\frac{2}{3} x + \frac{3}{5} y)

(1 - cos (t))^{2} + (sin (t))^{2}

\frac{s ^{2} + 6 s + 12}{( s + 2 ) ( s ^{2} + 4 s + 8 )}

What is expand (e^x-e^{-x})(e^x+e^{-x}) ?
The solution to expand (e^x-e^{-x})(e^x+e^{-x}) is e^{2x}-e^{-2x}