What is expand-(3u^2+2u-2)/(u(u^3-1)) ?

The solution to expand-(3u^2+2u-2)/(u(u^3-1)) is -(3u^2+2u-2)/(u^4-u)

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expand-(3u^2+2u-2)/(u(u^3-1))

expand

- \frac{3 u ^{2} + 2 u - 2}{u ( u ^{3} - 1 )}

- \frac{3 u ^{2} + 2 u - 2}{u ^{4} - u}

Solution steps

- \frac{3 u ^{2} + 2 u - 2}{u ( u ^{3} - 1 )}

Expand

u (u^{3} - 1) : u^{4} - u

= - \frac{3 u ^{2} + 2 u - 2}{u ^{4} - u}

8 cos^{2} (2 t) + (t - 5)^{2} - 7 e^{4 t}

δ (x - 3)

\frac{- x ^{2} - 9}{( x ^{2} - 9 ) ^{2}}

ln (x^{2} (x + 2))

(2 x - 5) (2 x + 5)

What is expand-(3u^2+2u-2)/(u(u^3-1)) ?
The solution to expand-(3u^2+2u-2)/(u(u^3-1)) is -(3u^2+2u-2)/(u^4-u)