What are the solutions to the equation x^2-9=-x^2+9 ?

The solutions to the equation x^2-9=-x^2+9 are x=3,x=-3

Find the zeros of x^2-9=-x^2+9

The zeros of x^2-9=-x^2+9 are x=3,x=-3

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x^{2} - 9 = - x^{2} + 9

x = 3, x = - 3

Solution steps

x^{2} - 9 = - x^{2} + 9

Move

9

to the right side

x^{2} = - x^{2} + 18

Move

x^{2}

to the left side

2 x^{2} = 18

Divide both sides by

2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

(\frac{1}{8})^{x - 6} < 4^{4 x + 5}

4 x - 1 < 11

- 58 = 3 x - 5 (2 x - 1)

x - 5 > 2 x

2 x^{2} + 11 x - 6 < 0

What are the solutions to the equation x^2-9=-x^2+9 ?
The solutions to the equation x^2-9=-x^2+9 are x=3,x=-3
Find the zeros of x^2-9=-x^2+9
The zeros of x^2-9=-x^2+9 are x=3,x=-3