What is expand 1/2 (e^x+e^{-x}) ?

The solution to expand 1/2 (e^x+e^{-x}) is 1/2 e^x+1/2 e^{-x}

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expand 1/2 (e^x+e^{-x})

expand

\frac{1}{2} (e^{x} + e^{- x})

\frac{1}{2} e^{x} + \frac{1}{2} e^{- x}

Solution steps

\frac{1}{2} (e^{x} + e^{- x})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{2}, b = e^{x}, c = e^{- x}

= \frac{1}{2} e^{x} + \frac{1}{2} e^{- x}

(x - 3 i)^{2}

\frac{2}{( x + 1 ) ^{3}}

(2 + 2 cos (θ))^{2}

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

\frac{s}{( s ^{2} + 1 ) ^{2}}

What is expand 1/2 (e^x+e^{-x}) ?
The solution to expand 1/2 (e^x+e^{-x}) is 1/2 e^x+1/2 e^{-x}