What is (4+1/x)(2-3/x) ?

The solution to (4+1/x)(2-3/x) is ((4x+1)(2x-3))/(x^2)

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simplify (4+1/x)(2-3/x)

simplify

(4 + \frac{1}{x}) (2 - \frac{3}{x})

\frac{( 4 x + 1 ) ( 2 x - 3 )}{x ^{2}}

Solution steps

(4 + \frac{1}{x}) (2 - \frac{3}{x})

Join

4 + \frac{1}{x} : \frac{4 x + 1}{x}

= \frac{4 x + 1}{x} (2 - \frac{3}{x})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 4 x + 1 ) ( 2 - \frac{3}{x} )}{x}

Simplify

(4 x + 1) (2 - \frac{3}{x}) : \frac{( 4 x + 1 ) ( 2 x - 3 )}{x}

= \frac{\frac{( 4 x + 1 ) ( 2 x - 3 )}{x}}{x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 4 x + 1 ) ( 2 x - 3 )}{xx}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{( 4 x + 1 ) ( 2 x - 3 )}{x ^{2}}

\frac{( 1 + j ) ^{6}}{( 1 - j ) ^{2} ( 2 + j ) ^{4}}

(3 x - 2)^{2}

(cos (θ) + i sin (θ))^{5}

2 (\frac{5}{e ^{4}} + \frac{5}{e ^{16}} + \frac{5}{e ^{36}})

(2 - 3 i)^{4}