What is (\partial)/(\partial x)((y)(x^2+y^2)) ?

The answer to (\partial)/(\partial x)((y)(x^2+y^2)) is 2yx

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(\partial)/(\partial x)((y)(x^2+y^2))

\frac{\partial}{\partial x} ((y) (x^{2} + y^{2}))

2 y x

Solution steps

\frac{\partial}{\partial x} ((y) (x^{2} + y^{2}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (x^{2} + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= y (2 x + 0)

Simplify

= 2 y x

\frac{a - bi}{1 + ( a + bi ) ^{2}}

(a^{2} - \frac{1}{a})^{4}

(7) (2 + 23)

(x^{2} + 2 x + 1) (x^{2} - 2 x + 1)

2 (2 + 3)

What is (\partial)/(\partial x)((y)(x^2+y^2)) ?
The answer to (\partial)/(\partial x)((y)(x^2+y^2)) is 2yx