What is expand ((4y^4-9)^2)/(144y^4) ?

The solution to expand ((4y^4-9)^2)/(144y^4) is (y^4)/9-1/2+9/(16y^4)

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expand ((4y^4-9)^2)/(144y^4)

expand

\frac{( 4 y ^{4} - 9 ) ^{2}}{144 y ^{4}}

\frac{y ^{4}}{9} - \frac{1}{2} + \frac{9}{16 y ^{4}}

Solution steps

\frac{( 4 y ^{4} - 9 ) ^{2}}{144 y ^{4}}

(4 y^{4} - 9)^{2} = 16 y^{8} - 72 y^{4} + 81

= \frac{16 y ^{8} - 72 y ^{4} + 81}{144 y ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 y ^{8} - 72 y ^{4} + 81}{144 y ^{4}} = \frac{16 y ^{8}}{144 y ^{4}} - \frac{72 y ^{4}}{144 y ^{4}} + \frac{81}{144 y ^{4}}

= \frac{16 y ^{8}}{144 y ^{4}} - \frac{72 y ^{4}}{144 y ^{4}} + \frac{81}{144 y ^{4}}

Cancel

\frac{16 y ^{8}}{144 y ^{4}} : \frac{y ^{4}}{9}

= \frac{y ^{4}}{9} - \frac{72 y ^{4}}{144 y ^{4}} + \frac{81}{144 y ^{4}}

Cancel

\frac{72 y ^{4}}{144 y ^{4}} : \frac{1}{2}

= \frac{y ^{4}}{9} - \frac{1}{2} + \frac{81}{144 y ^{4}}

Cancel

\frac{81}{144 y ^{4}} : \frac{9}{16 y ^{4}}

= \frac{y ^{4}}{9} - \frac{1}{2} + \frac{9}{16 y ^{4}}

(4 x - i)^{2}

2 (1 + 3)

(1 + 2 x)^{2}

(cos (x) - sec (x))^{2}

(x + y) d x + (x - y) d y

What is expand ((4y^4-9)^2)/(144y^4) ?
The solution to expand ((4y^4-9)^2)/(144y^4) is (y^4)/9-1/2+9/(16y^4)