What is expand (e^x-1)(e^x+1) ?

The solution to expand (e^x-1)(e^x+1) is e^{2x}-1

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expand (e^x-1)(e^x+1)

expand

(e^{x} - 1) (e^{x} + 1)

e^{2 x} - 1

Solution steps

(e^{x} - 1) (e^{x} + 1)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{x}, b = 1

= (e^{x})^{2} - 1^{2}

Simplify

(e^{x})^{2} - 1^{2} : e^{2 x} - 1

= e^{2 x} - 1

(x - 4 i)^{2}

\frac{5}{s ( s ^{2} + s + 2 )}

\frac{n ( n + 1 )}{2} + (n + 1)

\frac{6}{( s - 2 ) ^{4}}

\frac{1}{s ( T s + 1 )}

What is expand (e^x-1)(e^x+1) ?
The solution to expand (e^x-1)(e^x+1) is e^{2x}-1