What are the solutions to the equation (t+1/3)(t+2/3)=0 ?

The solutions to the equation (t+1/3)(t+2/3)=0 are t=-1/3 ,t=-2/3

Find the zeros of (t+1/3)(t+2/3)=0

The zeros of (t+1/3)(t+2/3)=0 are t=-1/3 ,t=-2/3

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(t + \frac{1}{3}) (t + \frac{2}{3}) = 0

t = - \frac{1}{3}, t = - \frac{2}{3}

Decimal Notation

t = - 0.33333 \dots, t = - 0.66666 \dots

Solution steps

(t + \frac{1}{3}) (t + \frac{2}{3}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t + \frac{1}{3} = 0 or t + \frac{2}{3} = 0

Solve

t + \frac{1}{3} = 0 : t = - \frac{1}{3}

Solve

t + \frac{2}{3} = 0 : t = - \frac{2}{3}

The solutions to the quadratic equation are:

t = - \frac{1}{3}, t = - \frac{2}{3}

2 x - 4 \leq 12

\frac{a - 3}{9 a ^{3} - 27 a ^{2}} + 3

6 x^{2} - 14 x + 4

4 x^{2} - 12 x + 8 = 0

8

What are the solutions to the equation (t+1/3)(t+2/3)=0 ?
The solutions to the equation (t+1/3)(t+2/3)=0 are t=-1/3 ,t=-2/3
Find the zeros of (t+1/3)(t+2/3)=0
The zeros of (t+1/3)(t+2/3)=0 are t=-1/3 ,t=-2/3