What is expand (4(x+3)(x-3))/((x+2)(x-4)) ?

The solution to expand (4(x+3)(x-3))/((x+2)(x-4)) is (4x^2-36)/(x^2-2x-8)

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expand (4(x+3)(x-3))/((x+2)(x-4))

expand

\frac{4 ( x + 3 ) ( x - 3 )}{( x + 2 ) ( x - 4 )}

\frac{4 x ^{2} - 36}{x ^{2} - 2 x - 8}

Solution steps

\frac{4 ( x + 3 ) ( x - 3 )}{( x + 2 ) ( x - 4 )}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{4 ( x + 3 ) ( x - 3 )}{x ^{2} - 2 x - 8}

Expand

4 (x + 3) (x - 3) : 4 x^{2} - 36

= \frac{4 x ^{2} - 36}{x ^{2} - 2 x - 8}

(x^{2} + \frac{1}{x})^{6}

(x^{\frac{1}{2}} + y^{\frac{1}{2}})^{2}

2 (2 - 3) 2 + 3

(x + 1) e^{x}

(1 - 3 i)^{4}

What is expand (4(x+3)(x-3))/((x+2)(x-4)) ?
The solution to expand (4(x+3)(x-3))/((x+2)(x-4)) is (4x^2-36)/(x^2-2x-8)