What is expand e^t(cos(2t)-sin(2t))^2 ?

The solution to expand e^t(cos(2t)-sin(2t))^2 is e^t(-sin(4t)+1)

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expand e^t(cos(2t)-sin(2t))^2

expand

e^{t} (cos (2 t) - sin (2 t))^{2}

e^{t} (- sin (4 t) + 1)

Solution steps

e^{t} (cos (2 t) - sin (2 t))^{2}

(cos (2 t) - sin (2 t))^{2} = cos^{2} (2 t) - sin (4 t) + sin^{2} (2 t)

= e^{t} (cos^{2} (2 t) + sin^{2} (2 t) - sin (4 t))

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= e^{t} (- sin (4 t) + 1)

lo g_{10} (4) x^{3}

(2 - y)^{2}

\frac{( 1 - cos ( x ) ) ^{2} + sin ^{2} ( x )}{1 - cos ( x )}

(x + \frac{1}{x})^{3}

(4 + 2) (6 - 2)

What is expand e^t(cos(2t)-sin(2t))^2 ?
The solution to expand e^t(cos(2t)-sin(2t))^2 is e^t(-sin(4t)+1)