What is expand (2x^2-3)/((x^2-9)(x^2-4)) ?

The solution to expand (2x^2-3)/((x^2-9)(x^2-4)) is (2x^2-3)/(x^4-13x^2+36)

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expand (2x^2-3)/((x^2-9)(x^2-4))

expand

\frac{2 x ^{2} - 3}{( x ^{2} - 9 ) ( x ^{2} - 4 )}

\frac{2 x ^{2} - 3}{x ^{4} - 13 x ^{2} + 36}

Solution steps

\frac{2 x ^{2} - 3}{( x ^{2} - 9 ) ( x ^{2} - 4 )}

Expand

(x^{2} - 9) (x^{2} - 4) : x^{4} - 13 x^{2} + 36

= \frac{2 x ^{2} - 3}{x ^{4} - 13 x ^{2} + 36}

\frac{1}{s ( s - a ) ^{2}}

(2 + x)^{4} (1 + \frac{1}{x ^{2}})

\frac{2 ( 1 - cos ( t ) )}{t}

(2 x + 3)^{2}

(1 - i)^{9}

What is expand (2x^2-3)/((x^2-9)(x^2-4)) ?
The solution to expand (2x^2-3)/((x^2-9)(x^2-4)) is (2x^2-3)/(x^4-13x^2+36)