What is expand (1+sin(t))^2 ?

The solution to expand (1+sin(t))^2 is 1+2sin(t)+sin^2(t)

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expand (1+sin(t))^2

expand

(1 + sin (t))^{2}

1 + 2 sin (t) + sin^{2} (t)

Solution steps

(1 + sin (t))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(1 + sin (t))^{2} = 1^{2} + 2 \cdot 1 \cdot sin (t) + sin^{2} (t)

= 1^{2} + 2 \cdot 1 \cdot sin (t) + sin^{2} (t)

Simplify

1^{2} + 2 \cdot 1 \cdot sin (t) + sin^{2} (t) : 1 + 2 sin (t) + sin^{2} (t)

= 1 + 2 sin (t) + sin^{2} (t)

sin (x) (1 - cos (x))

(1 - 6 x i)^{2}

\frac{5 ( 4 x - 13 )}{3}

\frac{x + 1}{x ^{2} ( x - 1 )}

(4 + h) \cdot 16 - h^{2}

What is expand (1+sin(t))^2 ?
The solution to expand (1+sin(t))^2 is 1+2sin(t)+sin^2(t)