What is expand (3-3/2 y)^3 ?

The solution to expand (3-3/2 y)^3 is (216-324y-27y^3+162y^2)/8

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expand (3-3/2 y)^3

expand

(3 - \frac{3}{2} y)^{3}

\frac{216 - 324 y - 27 y ^{3} + 162 y ^{2}}{8}

Solution steps

(3 - \frac{3}{2} y)^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(3 - \frac{3}{2} y)^{3} = 3^{3} - 3 \cdot 3^{2} \cdot \frac{3}{2} y + 3 \cdot 3 (\frac{3}{2} y)^{2} - (\frac{3}{2} y)^{3}

= 3^{3} - 3 \cdot 3^{2} \cdot \frac{3}{2} y + 3 \cdot 3 (\frac{3}{2} y)^{2} - (\frac{3}{2} y)^{3}

Simplify

3^{3} - 3 \cdot 3^{2} \cdot \frac{3}{2} y + 3 \cdot 3 (\frac{3}{2} y)^{2} - (\frac{3}{2} y)^{3} : \frac{216 - 324 y - 27 y ^{3} + 162 y ^{2}}{8}

= \frac{216 - 324 y - 27 y ^{3} + 162 y ^{2}}{8}

- x (x^{3} + y) d y

(x - 1 - 3) (x - 1 + 3)

(3 + 2 i)^{5}

(x - 32)^{2}

(1, - 5) y (- 2, 1)

What is expand (3-3/2 y)^3 ?
The solution to expand (3-3/2 y)^3 is (216-324y-27y^3+162y^2)/8