What is (\partial)/(\partial x)((z)(3xz-z^3+yz)) ?

The answer to (\partial)/(\partial x)((z)(3xz-z^3+yz)) is 3z^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((z)(3xz-z^3+yz))

\frac{\partial}{\partial x} ((z) (3 x z - z^{3} + yz))

3 z^{2}

Solution steps

\frac{\partial}{\partial x} ((z) (3 x z - z^{3} + yz))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (3 x z - z^{3} + yz)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (3 x z) - \frac{\partial}{\partial x} (z^{3}) + \frac{\partial}{\partial x} (yz))

\frac{\partial}{\partial x} (3 x z) = 3 z

\frac{\partial}{\partial x} (z^{3}) = 0

\frac{\partial}{\partial x} (yz) = 0

= z (3 z - 0 + 0)

Simplify

z (3 z - 0 + 0) : 3 z^{2}

= 3 z^{2}

(- 3 + i)^{8}

(sin (2 x) - cos (2 x))^{2}

x (x + 3)

(3 + 3 cos (θ))^{2}

What is (\partial)/(\partial x)((z)(3xz-z^3+yz)) ?
The answer to (\partial)/(\partial x)((z)(3xz-z^3+yz)) is 3z^2