What is expand (2(s^2-3))/((s+2)^2(s-2)^2) ?

The solution to expand (2(s^2-3))/((s+2)^2(s-2)^2) is (2s^2-6)/(s^4-8s^2+16)

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expand (2(s^2-3))/((s+2)^2(s-2)^2)

expand

\frac{2 ( s ^{2} - 3 )}{( s + 2 ) ^{2} ( s - 2 ) ^{2}}

\frac{2 s ^{2} - 6}{s ^{4} - 8 s ^{2} + 16}

Solution steps

\frac{2 ( s ^{2} - 3 )}{( s + 2 ) ^{2} ( s - 2 ) ^{2}}

(s + 2)^{2} = s^{2} + 4 s + 4

= \frac{2 ( s ^{2} - 3 )}{( s ^{2} + 4 s + 4 ) ( s - 2 ) ^{2}}

(s - 2)^{2} = s^{2} - 4 s + 4

= \frac{2 ( s ^{2} - 3 )}{( s ^{2} + 4 s + 4 ) ( s ^{2} - 4 s + 4 )}

Expand

(s^{2} + 4 s + 4) (s^{2} - 4 s + 4) : s^{4} - 8 s^{2} + 16

= \frac{2 ( s ^{2} - 3 )}{s ^{4} - 8 s ^{2} + 16}

Expand

2 (s^{2} - 3) : 2 s^{2} - 6

= \frac{2 s ^{2} - 6}{s ^{4} - 8 s ^{2} + 16}

(8 x + 9 x^{2} y^{2}) d x + 6 x^{3} y d y

(x - 7)^{2}

\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}}

(t - sin (t)) (1 - cos (t))

(x + 1) (x + \frac{1}{2})

What is expand (2(s^2-3))/((s+2)^2(s-2)^2) ?
The solution to expand (2(s^2-3))/((s+2)^2(s-2)^2) is (2s^2-6)/(s^4-8s^2+16)