What is expand (1/4+1/(2^{k+1)})(1-1/(2^{k+1)}) ?

The solution to expand (1/4+1/(2^{k+1)})(1-1/(2^{k+1)}) is 1/4-1/(2^{k+3)}+1/(2^{k+1)}-1/(4^{k+1)}

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expand (1/4+1/(2^{k+1)})(1-1/(2^{k+1)})

expand

(\frac{1}{4} + \frac{1}{2 ^{k + 1}}) (1 - \frac{1}{2 ^{k + 1}})

\frac{1}{4} - \frac{1}{2 ^{k + 3}} + \frac{1}{2 ^{k + 1}} - \frac{1}{4 ^{k + 1}}

Solution steps

(\frac{1}{4} + \frac{1}{2 ^{k + 1}}) (1 - \frac{1}{2 ^{k + 1}})

Apply FOIL method

(\frac{1}{4} + \frac{1}{2 ^{k + 1}}) (1 - \frac{1}{2 ^{k + 1}}) : \frac{1}{4} - \frac{1}{2 ^{k + 3}} + \frac{1}{2 ^{k + 1}} - \frac{1}{4 ^{k + 1}}

= \frac{1}{4} - \frac{1}{2 ^{k + 3}} + \frac{1}{2 ^{k + 1}} - \frac{1}{4 ^{k + 1}}

(x + 25) (x - 25)

\frac{f ( x + h ) - f ( x )}{h}

(5 z + 3 i)^{2}

(\frac{e ^{x} - e ^{- x}}{2})^{2}

(7 - 2 x - x + 2)^{2}

What is expand (1/4+1/(2^{k+1)})(1-1/(2^{k+1)}) ?
The solution to expand (1/4+1/(2^{k+1)})(1-1/(2^{k+1)}) is 1/4-1/(2^{k+3)}+1/(2^{k+1)}-1/(4^{k+1)}