What are the solutions to the equation -3x^2+2=0 ?

The solutions to the equation -3x^2+2=0 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of -3x^2+2=0

The zeros of -3x^2+2=0 are x=sqrt(2/3),x=-sqrt(2/3)

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- 3 x^{2} + 2 = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

- 3 x^{2} + 2 = 0

Move

2

to the right side

- 3 x^{2} = - 2

Divide both sides by

- 3

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

6 x^{2} - 30 = 0

\frac{a ^{2}}{\frac{4}{5} - \frac{4}{a}}

\frac{1200}{2.55 \cdot 1 0 ^{- 5}}

\frac{x}{3} - (- 2) = 16

(\frac{4}{5})^{3}

What are the solutions to the equation -3x^2+2=0 ?
The solutions to the equation -3x^2+2=0 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of -3x^2+2=0
The zeros of -3x^2+2=0 are x=sqrt(2/3),x=-sqrt(2/3)