What is expand (2(2x^2-x+3))/x ?

The solution to expand (2(2x^2-x+3))/x is 4x-2+6/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2(2x^2-x+3))/x

expand

\frac{2 ( 2 x ^{2} - x + 3 )}{x}

4 x - 2 + \frac{6}{x}

Solution steps

\frac{2 ( 2 x ^{2} - x + 3 )}{x}

Expand

2 (2 x^{2} - x + 3) : 4 x^{2} - 2 x + 6

= \frac{4 x ^{2} - 2 x + 6}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 2 x + 6}{x} = \frac{4 x ^{2}}{x} - \frac{2 x}{x} + \frac{6}{x}

= \frac{4 x ^{2}}{x} - \frac{2 x}{x} + \frac{6}{x}

Cancel

\frac{4 x ^{2}}{x} : 4 x

= 4 x - \frac{2 x}{x} + \frac{6}{x}

Cancel

\frac{2 x}{x} : 2

= 4 x - 2 + \frac{6}{x}

(sin (3 t) + cos (3 t))^{2}

ln^{x^{2}} (x) (2 x ln (ln (x)) + \frac{x}{ln ( x )})

(2 x - 2) (2 x + 2)

(4 - y i)^{2}

(270 + 905) c m^{3}

What is expand (2(2x^2-x+3))/x ?
The solution to expand (2(2x^2-x+3))/x is 4x-2+6/x