What is (a-1/9)(a+1/9) ?

The solution to (a-1/9)(a+1/9) is ((9a-1)(9a+1))/(81)

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simplify (a-1/9)(a+1/9)

simplify

(a - \frac{1}{9}) (a + \frac{1}{9})

\frac{( 9 a - 1 ) ( 9 a + 1 )}{81}

Solution steps

(a - \frac{1}{9}) (a + \frac{1}{9})

Simplify

a - \frac{1}{9} : \frac{9 a - 1}{9}

= \frac{9 a - 1}{9} (a + \frac{1}{9})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 9 a - 1 ) ( a + \frac{1}{9} )}{9}

Simplify

(9 a - 1) (a + \frac{1}{9}) : \frac{( 9 a - 1 ) ( a \cdot 9 + 1 )}{9}

= \frac{\frac{( 9 a - 1 ) ( a \cdot 9 + 1 )}{9}}{9}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 9 a - 1 ) ( a \cdot 9 + 1 )}{9 \cdot 9}

Multiply the numbers:

9 \cdot 9 = 81

= \frac{( 9 a - 1 ) ( a \cdot 9 + 1 )}{81}

= \frac{( 9 a - 1 ) ( 9 a + 1 )}{81}

(\frac{3}{4} x - \frac{2}{3} y) (\frac{3}{4} x + \frac{2}{3} y)

\frac{( n + 1 ) ^{2} ( n + 2 ) ^{2}}{4}

\frac{1}{( x - 1 ) ^{3}}

(e^{t} + e^{3 t})^{2}