What is expand ((x-4)(x-1)(x+3))/((x-3)(x+2)) ?

The solution to expand ((x-4)(x-1)(x+3))/((x-3)(x+2)) is (x^3-2x^2-11x+12)/(x^2-x-6)

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expand ((x-4)(x-1)(x+3))/((x-3)(x+2))

expand

\frac{( x - 4 ) ( x - 1 ) ( x + 3 )}{( x - 3 ) ( x + 2 )}

\frac{x ^{3} - 2 x ^{2} - 11 x + 12}{x ^{2} - x - 6}

Solution steps

\frac{( x - 4 ) ( x - 1 ) ( x + 3 )}{( x - 3 ) ( x + 2 )}

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= \frac{( x - 4 ) ( x - 1 ) ( x + 3 )}{x ^{2} - x - 6}

Expand

(x - 4) (x - 1) (x + 3) : x^{3} - 2 x^{2} - 11 x + 12

= \frac{x ^{3} - 2 x ^{2} - 11 x + 12}{x ^{2} - x - 6}

(e - 1)^{2}

\frac{( 2 - x ) ^{3}}{3 ( x - 1 ) ^{2}}

\frac{1}{x ( x + 3 )}

x + 2 (3 - \frac{4}{x + 2})

(z - i)^{3}

What is expand ((x-4)(x-1)(x+3))/((x-3)(x+2)) ?
The solution to expand ((x-4)(x-1)(x+3))/((x-3)(x+2)) is (x^3-2x^2-11x+12)/(x^2-x-6)