What is expand sin(t)U(t-2pi) ?

The solution to expand sin(t)U(t-2pi) is tUsin(t)-2piUsin(t)

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expand sin(t)U(t-2pi)

expand

sin (t) U (t - 2 π)

t U sin (t) - 2 π U sin (t)

Solution steps

sin (t) U (t - 2 π)

= U sin (t) (t - 2 π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) U, b = t, c = 2 π

= sin (t) U t - sin (t) U \cdot 2 π

= t U sin (t) - 2 π U sin (t)

\frac{1}{( x + 5 ) ^{2}}

\frac{s}{( s + 3 ) ( s + 5 )}

(u - u) (u + u)

(a + ib)^{3}

x^{\frac{2}{3}} (x - 2)

What is expand sin(t)U(t-2pi) ?
The solution to expand sin(t)U(t-2pi) is tUsin(t)-2piUsin(t)