What is expand 5/((x^2+4)(x^2-1)) ?

The solution to expand 5/((x^2+4)(x^2-1)) is 5/(x^4+3x^2-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 5/((x^2+4)(x^2-1))

expand

\frac{5}{( x ^{2} + 4 ) ( x ^{2} - 1 )}

\frac{5}{x ^{4} + 3 x ^{2} - 4}

Solution steps

\frac{5}{( x ^{2} + 4 ) ( x ^{2} - 1 )}

Expand

(x^{2} + 4) (x^{2} - 1) : x^{4} + 3 x^{2} - 4

= \frac{5}{x ^{4} + 3 x ^{2} - 4}

\frac{3 x ^{2}}{( x + 3 ) ^{2}}

\frac{( x - 1 ) ^{2}}{2}

(3 z - \frac{2}{z})^{7}

\frac{1}{( 1 + 2 x ) ^{4}}

\frac{( x + 1 ) ^{3}}{x ^{2}}

What is expand 5/((x^2+4)(x^2-1)) ?
The solution to expand 5/((x^2+4)(x^2-1)) is 5/(x^4+3x^2-4)