What is 1/8 (3+4cos(2x)+cos(4x)) ?

The solution to 1/8 (3+4cos(2x)+cos(4x)) is (3+cos(4x))/8+(cos(2x))/2

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simplify 1/8 (3+4cos(2x)+cos(4x))

simplify

\frac{1}{8} (3 + 4 cos (2 x) + cos (4 x))

\frac{3 + cos ( 4 x )}{8} + \frac{cos ( 2 x )}{2}

Solution steps

\frac{1}{8} (3 + 4 cos (2 x) + cos (4 x))

Expand

\frac{1}{8} (3 + 4 cos (2 x) + cos (4 x)) : \frac{3 + cos ( 4 x )}{8} + \frac{cos ( 2 x )}{2}

= \frac{3 + cos ( 4 x )}{8} + \frac{cos ( 2 x )}{2}

(e^{x} + 2)^{2}

(cos (2 x) + sin (2 x))^{2}

cos (x) (1 - sec (x)) + 1

\frac{e ^{- s}}{s ( s ^{2} - 5 s + 6 )}

2 π r (h + r)

What is 1/8 (3+4cos(2x)+cos(4x)) ?
The solution to 1/8 (3+4cos(2x)+cos(4x)) is (3+cos(4x))/8+(cos(2x))/2