What is the d/(dt)((h(t))(2.8t+2.5)) ?

The d/(dt)((h(t))(2.8t+2.5)) is h(5.6t+2.5)

What is the first d/(dt)((h(t))(2.8t+2.5)) ?

The first d/(dt)((h(t))(2.8t+2.5)) is h(5.6t+2.5)

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\frac{d}{d t} ((h (t)) (2.8 t + 2.5))

h (5.6 t + 2.5)

Solution steps

\frac{d}{d t} ((h (t)) (2.8 t + 2.5))

Treat

h

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= h \frac{d}{d t} (t (2.8 t + 2.5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = 2.8 t + 2.5

= h (\frac{d t}{d t} (2.8 t + 2.5) + \frac{d}{d t} (2.8 t + 2.5) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (2.8 t + 2.5) = 2.8

= h (1 \cdot (2.8 t + 2.5) + 2.8 t)

Simplify

= h (5.6 t + 2.5)

(4 + 5 y i)^{2}

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(5 - 2 x i)^{2}

(3 sin (x) + 3 cos (x))^{2}

5 (x + Δ x)^{2}

What is the d/(dt)((h(t))(2.8t+2.5)) ?
The d/(dt)((h(t))(2.8t+2.5)) is h(5.6t+2.5)
What is the first d/(dt)((h(t))(2.8t+2.5)) ?
The first d/(dt)((h(t))(2.8t+2.5)) is h(5.6t+2.5)