What is expand x^{1/3}(x^2-4) ?

The solution to expand x^{1/3}(x^2-4) is x^{7/3}-x^{1/3}*4

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expand x^{1/3}(x^2-4)

expand

x^{\frac{1}{3}} (x^{2} - 4)

x^{\frac{7}{3}} - x^{\frac{1}{3}} \cdot 4

Solution steps

x^{\frac{1}{3}} (x^{2} - 4)

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{1}{3}} (x^{2} - 4) = x^{\frac{1}{3}} x^{2} - x^{\frac{1}{3}} \cdot 4

= x^{\frac{1}{3}} x^{2} - x^{\frac{1}{3}} \cdot 4

Simplify

x^{\frac{1}{3}} x^{2} : x^{\frac{7}{3}}

= x^{\frac{7}{3}} - x^{\frac{1}{3}} \cdot 4

\frac{10}{( s + 2 ) ( s + 1 ) ^{3}}

5 (10 + 2)

8 \cdot (\frac{x}{2} + \frac{1}{4})

(y^{2} + x y^{3}) d x + (5 y^{2} - x y + y^{3} sin (y)) d y

(x + sin (x))^{2}

What is expand x^{1/3}(x^2-4) ?
The solution to expand x^{1/3}(x^2-4) is x^{7/3}-x^{1/3}*4