What is expand ((2-2x)^3)/3 ?

The solution to expand ((2-2x)^3)/3 is -(8x^3)/3+8x^2-8x+8/3

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expand ((2-2x)^3)/3

expand

\frac{( 2 - 2 x ) ^{3}}{3}

- \frac{8 x ^{3}}{3} + 8 x^{2} - 8 x + \frac{8}{3}

Solution steps

\frac{( 2 - 2 x ) ^{3}}{3}

(2 - 2 x)^{3} = 8 - 24 x + 24 x^{2} - 8 x^{3}

= \frac{8 - 24 x + 24 x ^{2} - 8 x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 - 24 x + 24 x ^{2} - 8 x ^{3}}{3} = \frac{8}{3} - \frac{24 x}{3} + \frac{24 x ^{2}}{3} - \frac{8 x ^{3}}{3}

= \frac{8}{3} - \frac{24 x}{3} + \frac{24 x ^{2}}{3} - \frac{8 x ^{3}}{3}

Divide the numbers:

\frac{24}{3} = 8

= \frac{8}{3} - 8 x + 8 x^{2} - \frac{8 x ^{3}}{3}

Rewrite in standard form

= - \frac{8 x ^{3}}{3} + 8 x^{2} - 8 x + \frac{8}{3}

\frac{d ^{2}}{d x ^{2}} ((y) (x cos (5 x) - sin^{2} (x)))

2 (cos (5 x) + cos (3 x)) (sin (3 x) - sin (x))

s (1 + \frac{s}{3}) (1 + \frac{s}{20})

\frac{( 6 x ^{2} - 3 ) ^{4}}{( 2 x ^{3} + 8 ) ^{5}}

3 (3 - 1)

What is expand ((2-2x)^3)/3 ?
The solution to expand ((2-2x)^3)/3 is -(8x^3)/3+8x^2-8x+8/3