What is expand log_{10}(\sqrt[3]{xy^4z^2}) ?

The solution to expand log_{10}(\sqrt[3]{xy^4z^2}) is log_{10}(y)+1/3 log_{10}(xyz^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{10}(\sqrt[3]{xy^4z^2})

expand

lo g_{10} (y) + \frac{1}{3} lo g_{10} (x y z^{2})

Solution steps

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

Simplify

= lo g_{10} (y) + \frac{1}{3} lo g_{10} (x y z^{2})

Simplify

lo g_{10} (x y z^{2}) : 2 lo g_{10} (z) + lo g_{10} (x y)

= lo g_{10} (y) + \frac{1}{3} (2 lo g_{10} (z) + lo g_{10} (x y))

lo g_{10} (x y) + 2 lo g_{10} (z) = lo g_{10} (x y z^{2})

= lo g_{10} (y) + \frac{1}{3} lo g_{10} (x y z^{2})

Simplify

lo g_{10} (x y z^{2}) : 2 lo g_{10} (z) + lo g_{10} (x y)

= lo g_{10} (y) + \frac{1}{3} (2 lo g_{10} (z) + lo g_{10} (x y))

lo g_{10} (x y) + 2 lo g_{10} (z) = lo g_{10} (x y z^{2})

= lo g_{10} (y) + \frac{1}{3} lo g_{10} (x y z^{2})

(1 - \frac{x}{2})^{2}

(e^{3 t} + e^{- 3 t})^{2}

(x + y i)^{5}

(2 e^{- 0.01 t} - e^{- 0.02 t})^{3}

tan (x) (cot (x) + 1)

What is expand log_{10}(\sqrt[3]{xy^4z^2}) ?
The solution to expand log_{10}(\sqrt[3]{xy^4z^2}) is log_{10}(y)+1/3 log_{10}(xyz^2)