What is expand log_{7}(2)(x+7)-log_{7}(x+1) ?

The solution to expand log_{7}(2)(x+7)-log_{7}(x+1) is log_{7}((2^{x+7})/(x+1))

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expand log_{7}(2)(x+7)-log_{7}(x+1)

expand

lo g_{7} (2) (x + 7) - lo g_{7} (x + 1)

lo g_{7} (\frac{2 ^{x + 7}}{x + 1})

Solution steps

lo g_{7} (2) (x + 7) - lo g_{7} (x + 1)

Expand

lo g_{7} (2) (x + 7) : lo g_{7} (2) x + lo g_{7} (2) \cdot 7

= lo g_{7} (2) x + lo g_{7} (2) \cdot 7 - lo g_{7} (x + 1)

Simplify

lo g_{7} (2) x + lo g_{7} (2) \cdot 7 - lo g_{7} (x + 1) : lo g_{7} (\frac{2 ^{x + 7}}{x + 1})

= lo g_{7} (\frac{2 ^{x + 7}}{x + 1})

\frac{k ( k + 1 ) ( k + 2 ) ( k + 3 )}{4}

(1 + tan (x)) tan (2 x)

(e + 3) (e - 5)

(5 - x) (x - \frac{x}{2})

What is expand log_{7}(2)(x+7)-log_{7}(x+1) ?
The solution to expand log_{7}(2)(x+7)-log_{7}(x+1) is log_{7}((2^{x+7})/(x+1))