What is expand-e^3f^2(e^2f^5+e-4f^2) ?

The solution to expand-e^3f^2(e^2f^5+e-4f^2) is -e^5f^7+4e^3f^4-e^4f^2

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expand-e^3f^2(e^2f^5+e-4f^2)

expand

- e^{3} f^{2} (e^{2} f^{5} + e - 4 f^{2})

- e^{5} f^{7} + 4 e^{3} f^{4} - e^{4} f^{2}

Solution steps

- e^{3} f^{2} (e^{2} f^{5} + e - 4 f^{2})

Distribute parentheses

= (- e^{3} f^{2}) e^{2} f^{5} + (- e^{3} f^{2}) e + (- e^{3} f^{2}) (- 4 f^{2})

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= - e^{3} e^{2} f^{5} f^{2} - e^{3} e f^{2} + 4 e^{3} f^{2} f^{2}

Simplify

- e^{3} e^{2} f^{5} f^{2} - e^{3} e f^{2} + 4 e^{3} f^{2} f^{2} : - e^{5} f^{7} + 4 e^{3} f^{4} - e^{4} f^{2}

= - e^{5} f^{7} + 4 e^{3} f^{4} - e^{4} f^{2}

2 (sin (x) + cos (x))

\frac{\partial}{\partial y} ((z) (6 x^{5} + 4 y^{3} + 4 y))

\frac{x ^{4}}{( 1 - x ) ^{3}}

(3 x + 2 y - 2) d x + (6 x + 4 y + 4) d y

ln (\frac{x ^{3}}{y ^{2}})

What is expand-e^3f^2(e^2f^5+e-4f^2) ?
The solution to expand-e^3f^2(e^2f^5+e-4f^2) is -e^5f^7+4e^3f^4-e^4f^2