What is expand ((x-6)n^n)/((n+1)^{n+1)} ?

The solution to expand ((x-6)n^n)/((n+1)^{n+1)} is (n^nx)/((n+1)^{n+1)}-(6n^n)/((n+1)^{n+1)}

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expand ((x-6)n^n)/((n+1)^{n+1)}

expand

\frac{( x - 6 ) n ^{n}}{( n + 1 ) ^{n + 1}}

\frac{n ^{n} x}{( n + 1 ) ^{n + 1}} - \frac{6 n ^{n}}{( n + 1 ) ^{n + 1}}

Solution steps

\frac{( x - 6 ) n ^{n}}{( n + 1 ) ^{n + 1}}

Expand

(x - 6) n^{n} : n^{n} x - 6 n^{n}

= \frac{n ^{n} x - 6 n ^{n}}{( n + 1 ) ^{n + 1}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{n} x - 6 n ^{n}}{( n + 1 ) ^{n + 1}} = \frac{n ^{n} x}{( n + 1 ) ^{n + 1}} - \frac{6 n ^{n}}{( n + 1 ) ^{n + 1}}

= \frac{n ^{n} x}{( n + 1 ) ^{n + 1}} - \frac{6 n ^{n}}{( n + 1 ) ^{n + 1}}

\frac{4 x ^{2} + 3}{( x - 1 ) ( x ^{2} + x + 5 )}

e^{2 x} (0.75 x - 1) + 0.75 x + 1

(2 - 3 - x) (2 + 3 - x)

(x - 3 - 2) (x - 3 + 2)

What is expand ((x-6)n^n)/((n+1)^{n+1)} ?
The solution to expand ((x-6)n^n)/((n+1)^{n+1)} is (n^nx)/((n+1)^{n+1)}-(6n^n)/((n+1)^{n+1)}