What is (y+1/3)(y-1/3) ?

The solution to (y+1/3)(y-1/3) is ((3y+1)(3y-1))/9

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simplify (y+1/3)(y-1/3)

simplify

(y + \frac{1}{3}) (y - \frac{1}{3})

\frac{( 3 y + 1 ) ( 3 y - 1 )}{9}

Solution steps

(y + \frac{1}{3}) (y - \frac{1}{3})

Simplify

y + \frac{1}{3} : \frac{3 y + 1}{3}

= \frac{3 y + 1}{3} (y - \frac{1}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 y + 1 ) ( y - \frac{1}{3} )}{3}

Simplify

(3 y + 1) (y - \frac{1}{3}) : \frac{( 3 y + 1 ) ( y \cdot 3 - 1 )}{3}

= \frac{\frac{( 3 y + 1 ) ( y \cdot 3 - 1 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 y + 1 ) ( y \cdot 3 - 1 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 3 y + 1 ) ( y \cdot 3 - 1 )}{9}

= \frac{( 3 y + 1 ) ( 3 y - 1 )}{9}

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