What is expand (1+4x)^{(-1)/2} ?

The solution to expand (1+4x)^{(-1)/2} is 1/((1+4x)^{1/2)}

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expand (1+4x)^{(-1)/2}

expand

(1 + 4 x)^{\frac{- 1}{2}}

\frac{1}{( 1 + 4 x ) ^{\frac{1}{2}}}

Solution steps

(1 + 4 x)^{\frac{- 1}{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= (1 + 4 x)^{- \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( 1 + 4 x ) ^{\frac{1}{2}}}

(1 - cos (x)) cos (x)

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(1 + sin (a)) \cdot (1 - sin (a))

(- 15 - - 9) - (3 - - 9)

\frac{2 ( s + 8 )}{s ^{2} + 4 s + 13}

What is expand (1+4x)^{(-1)/2} ?
The solution to expand (1+4x)^{(-1)/2} is 1/((1+4x)^{1/2)}