What is expand ((x+2)(x-4))/((x+4)(x-5)(x+1)) ?

The solution to expand ((x+2)(x-4))/((x+4)(x-5)(x+1)) is (x^2-2x-8)/(x^3-21x-20)

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expand ((x+2)(x-4))/((x+4)(x-5)(x+1))

expand

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )}

\frac{x ^{2} - 2 x - 8}{x ^{3} - 21 x - 20}

Solution steps

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )}

Expand

(x + 4) (x - 5) (x + 1) : x^{3} - 21 x - 20

= \frac{( x + 2 ) ( x - 4 )}{x ^{3} - 21 x - 20}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{x ^{3} - 21 x - 20}

- 4 x^{5} \cdot x^{5}

lo g_{10} (2) (x + 3)

\frac{1}{k ( k + 1 )}

\frac{1}{1 - x ^{2}}

- \frac{y ( 2 x + y )}{x ( x + 2 y )}

What is expand ((x+2)(x-4))/((x+4)(x-5)(x+1)) ?
The solution to expand ((x+2)(x-4))/((x+4)(x-5)(x+1)) is (x^2-2x-8)/(x^3-21x-20)